(x+2)(x^2+x-20)=0

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Solution for (x+2)(x^2+x-20)=0 equation: 


Simplifying
(x + 2)(x2 + x + -20) = 0

Reorder the terms:
(2 + x)(x2 + x + -20) = 0

Reorder the terms:
(2 + x)(-20 + x + x2) = 0

Multiply (2 + x) * (-20 + x + x2)
(2(-20 + x + x2) + x(-20 + x + x2)) = 0
((-20 * 2 + x * 2 + x2 * 2) + x(-20 + x + x2)) = 0
((-40 + 2x + 2x2) + x(-20 + x + x2)) = 0
(-40 + 2x + 2x2 + (-20 * x + x * x + x2 * x)) = 0
(-40 + 2x + 2x2 + (-20x + x2 + x3)) = 0

Reorder the terms:
(-40 + 2x + -20x + 2x2 + x2 + x3) = 0

Combine like terms: 2x + -20x = -18x
(-40 + -18x + 2x2 + x2 + x3) = 0

Combine like terms: 2x2 + x2 = 3x2
(-40 + -18x + 3x2 + x3) = 0

Solving
-40 + -18x + 3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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